Python Program to Check Leap Year

In this program, you will learn to check whether a year is leap year or not. We will use nested if…else to solve this problem.

# Python program to check if year is a leap year or not

year = 2004

# To get year (integer input) from the user
# year = int(input("Enter a year: "))

if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print("{0} is a leap year".format(year))
       else:
           print("{0} is not a leap year".format(year))
   else:
       print("{0} is a leap year".format(year))
else:
   print("{0} is not a leap year".format(year))

Output

2004 is a leap year